Question

Упростите выражение:Sin2a Cos2a (tg2a+ctg2a+2)

Answer 1

$sin2acos2a(tg2a+ctg2a+2)=sin2acos2a(frac{sin^22a}{cos^22a}+frac{cos^22a}{sin^22a}+2)=$ $=sin2acos2a(frac{sin^42a+cos^42a+2sin^22acos^22a}{sin^22acos^22a})=$ $=frac{sin2acos2a(sin^22a+cos^22a)^2}{sin^22acos^22a}=frac{1}{sin2acos2a}$