Question

log по основанию 12 x >3

Answer 1

$displaystyle log_frac{1}2x textgreater 3\\x textless bigg(frac{1}2bigg)^3\\x textless frac{1}8\\text{ODZ:}quad x textgreater 0\\ left { {x textless frac{1}8 atop x textgreater 0} right. ,,rightarrow quad boxed{xin bigg(0;frac{1}8bigg)}$