Question

log 6 основ 5 х log 0.2 основ 6

Answer 1

$log_56cdot log_6, 0,2= frac{1}{log_65} cdot log_6, 0,2= frac{log_6, 0,2}{log_65} =\\\star log_{a}, b= frac{log_{c}b}{log_{c}a} quad Rightarrow quad frac{log_{c}b}{log_{c}a}=log_{a}b ; ; ,; ; c=6,; b=0,2; ,; a=5; ; star \\\=log_5, 0,2=log_5 frac{2}{10} =log_5 frac{1}{5}=log_55^{-1} =-1cdot log_55=-1cdot 1=-1$