Question

log0,3(2x-4)>log0,3(x+1)

Answer 1

$log_{0,3}(2x-4) textgreater log_{0,3}(x+1)\0 textless 0,3 textless 1\\OD3: left { {{2x-4 textgreater 0} atop {x+1 textgreater 0}} right.= textgreater left { {{2x textgreater 4} atop {x textgreater -1}} right. = textgreater left { {{x textgreater 2} atop {x textgreater -1}} right. = textgreater x textgreater 2\\2x-4 textless x+1\2x-x textless 1+4\x textless 5\\xin(2;5)$