Question

1)tg3x=1
2)sin(x+π6)=-1

Answer 1

1)    tg3x=1  3x=π/4+πn   n∈Z

2)     sin(x+π6)=-1   x+π/6=-π/2+2πn    x=  x=-π/2-π/6+2πn    n∈Z