Question

найдите f'(Pi) , если f(x)=3x^2 × e^sinx -8

Answer 1

$f (x)=3x^2*e^{sinx}-8$
$f'(x)=3*2x*e^{sinx}+3x^2*e^{sinx}*cosx=3x*e^{sinx}(2+xcosx)$$f'( pi )=3 pi *e^{sin pi }(2+ pi cos pi )=3 pi *e^{0 }(2+ pi (-1) )= \ =3 pi (2-pi )=6 pi -3 pi ^{2}$