Question

x^4-5x^2+4/x^3-2x^2+2-x=0 СОКРАТИТЕ ДРОБЬ 

Answer 1

$frac{x^4-5x^2+4}{x^3-2x^2+2-x} =0\x^3-2x^2+2-x=0\x(x^2-1)-2(x^2-1)=0\(x^2-1)(x-2)=0\x=1\x=-1\x=2\..............................................\x neq 1\x neq -1\x neq 2\x^4-5x^2+4=0\x^2=t\t^2-5t+4=0\a+b+c=0\t_1=1\t_2=4\x^2=1\x=1\x=-1\x^2=4\x=2\x=-2$
ответ -2