Question

t^2+6t-16=0 пж срочно

Answer 1

$t^2+6t-16=0$

$D=b^2-4ac=6^2-4*1*(-16)=36+64=100=10^2$

$x_{1}= frac{6+10}{2}= frac{16}{2} =8$

$x_{2}= frac{6-10}{2} =- frac{-4}{2} =-2$