Question

2 sin²x - 5 sin x cos x -8 cos²x = -1
Помогите, пожалуйста

Answer 1

2sin^2x-5sinx*cosx-8cox^x=-1(sin^2x+cos^2x)
2sin^2x-5sinx*cosx-8cox^x+1(sin^2x+cos^2x)=0
3sin^2x-5sinx*cosx-7cos^2x=0
3tan^2x-5tanx-7=0
3t^2-5t-7=0
t=(5+√109)/6
t=(5-√109)/6
x=arctan(5+√109/6)+kπ, k∈Z
x=arctan(5-√109/6)+kπ, k∈Z