Question

упростить x+2/x+1 + x-2/1-x - x^2+1/x^2-1 ( ^2 -это степень)

Answer 1

$frac{x+2}{x+1} + frac{x-2}{1-x}- frac{x^2+1}{x^2-1} = frac{x+1+1}{x+1}- frac{x-1-1}{x-1} - frac{x^2-1+2}{x^2-1} =$
$=1+ frac{1}{x+1} -(1- frac{1}{x-1} )-(1+ frac{2}{(x-1)(x+1)} )=frac{1}{x+1}+frac{1}{x-1}-1-frac{2}{(x-1)(x+1)}$
$=-1+ frac{x-1}{(x+1)(x-1)} + frac{x+1}{(x+1)(x-1)} -frac{2}{(x-1)(x+1)}=-1+ frac{2x-2}{(x-1)(x+1)} =$
$=-1+ frac{2}{x+1} = frac{-x-1+2}{x+1} = frac{-x+1}{x+1} = frac{1-x}{1+x}$