Question

Вычислите интеграл от 1 до -2 (6x^2-2x+1)

Answer 1

$it int_{-2} ^1 (6x^2-2x+1)dx = left(6dfrac{ x^3}{3}-2dfrac{x^2}{2}+x right) Big{|}_{-2}^1 = \;\ \;\ =(2x^3-x^2+x) Big{|}_{-2}^1 = 2-1+1-(-16-4-2)=2+22=24$