Question

алгебра 10 класс (пример на фото)

Answer 1

$(x+1)^5+(x-1)^5=32x\(x+1)^5+((x-1)^5-32x)=0\(x+1)^5+(x^5-5x^4+10x^3-10x^2-27x-1)=0\((x+1)^4+(x^4-6x^3+16x^2-26x-1)(x+1)=0\((x^4+4x^3+6x^2+4x+1)+(x^4-6x^3+16x^2-26x-1))(x+1)=0\(x^4+4x^3+6x^2+4x+1+x^4-6x^3+16x^2-26x-1)(x+1)=0\(2x^4-2x^3+22x^2-22x)(x+1)=0\2x^4-2x^3+22x^2-22x=0\x^4-x^3+11x^2-11x=0\x(x^3-x^2+11x-11)=0\x=0\x^3-x^2+11x-11=0\x^2(x-1)+11(x-1)=0\(x^2+11)(x-1)=0\x^2+11=0\x^2 neq -11\x-1=0\x=1\x+1=0\x=-1$