Question

(2х-3)^2+(3-4х)(х+5)=82

Answer 1

$(2x-3)^2+(3-4x)(x+5)=82 \4x^2-12x+9+3x+15-4x^2-20x=82 \24-32x+3x=82 \-29x=82-24 \-29x=58 \x= frac{58}{-29} =-2$
Ответ: x=-2

Answer 2

$(2x-3)^{2}+(3-4x)(x+5)=82$
$4 x^{2}-12x+9+3x+15-4 x^{2}-20x=82$
$24-32x=82$
$-32x=106$
$x= frac{106}{-32}$
$x=3,3125$
Ответ: 3,3125