Question

решить (2х-1)^4 - х^2=0

Answer 1

$((2x-1)^{2})^{2}-x^{2}=0 ((2x-1)^{2}-x)((2x-1)^{2}+x)=0 (2x-1)^{2}-x=0 ; (2x-1)^{2}+x=0 4x^{2}-5x+1=0 d=9, x1=1,x2=1/4 4x^{2}-3x+1=0 d=-7, d leq 0$,