Question

(1-x):(x^2-xy)-(y-1):(y^2-xy) помогите решить

Answer 1

$frac{1-x}{x^2-xy}-frac{y-1}{y^2-xy}=frac{1-x}{x(x-y)}-frac{y-1}{y(y-x)}=frac{1-x}{x(x-y)}+frac{y-1}{y(x-y)}=\ =frac{y(1-x)+x(y-1)}{xy(x-y)}=frac{y-xy+xy-x}{xy(x-y)}=frac{y-x}{xy(x-y)}=-frac{x-y}{xy(x-y)}=-frac{1}{xy}$