Question

0.2^(2x-0.2)/0.2^(0.2x-2)=1

Answer 1

$frac{ 0,2^{2x-0,2} }{0,2 ^{0,2x-2} }=1$
$0,2^{(2x-0,2)-(0,2x-2)} =1$
$0,2^{1,8x+1,8}=1$
$0,2^{1,8x+1,8}= 0,2^{0}$
1,8x+1,8=0
x=-1