Question

НОМЕР 5 (Б, Е), НОМЕР 6 (В, Г)

Answer 1

5б
(x+4)²/[(x+4)+(x-4)²/x(x-4)=(x+4)/x+(x-4)/x=(x+4+x-4)/x=2x/x=2
5е
(x-1) +x/(x+1)-(x+2)/(x-1)(x+1)=[(x-1)(x²-1)+(x²+x)x-(x+2)]/(x²-1)=
=(x³-x-x²+1+x²-x-x-2)/(x²-1)=(x³-3x+1)/(x²-1)
6в
Ix-10)(x+10)/2x³ *(-x²)/(x-10)=-(x+10)/2x
6г
(x²-4):(x+2)²/(x-2)=(x-2)(x+2)*(x-2)/(x+2)²=(x-2)²(x+2)