Question

sinX-√3cosX=2
cosX-sinX=√2

Answer 1

SinX-√3cosX=2
2(1/2*sinx-√3/2cosx)=2
sin(x-π/3)=1
x-π/3=π/2+2πk
x=5π/6+2πk,k∈z

cosX-sinX=√2
√2(1/√2*cosx-1/√2*sinx)=√2
cos(x+π/4)=1
x+π/4=2πk
x=-π/4+2πk,k∈z