Предмет: Геометрия, автор: korolenko17

решите , пожалуйста, задачу .
Точка К - середина стороны ВС параллелограмма ABCD. Площадь параллелограмма ABCD равна 38. Найдите площадь треугольника AKD.

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Автор ответа: Shir00

0

площади треугольников авк ксд акд равны у них равные основания и высота тогда 38:3= 12 2/3

Автор ответа: korolenko17

0

а можно подробнее. с объяснением?

Автор ответа: Shir00

0

KK1 || AB || CD
KK1 разбивает параллелограмм ABCD на 2 параллелограмма, у каждого из которых диагонали AK и KD делят каждый параллелограмм на 2 равных треугольника (по свойству диагонали параллелограмма) => площадь каждого треугольника = 14 площади параллелограмма ABCD =>
S (AKD) = S (AKK1) + S (KDK1) = 2 * S (AKK1) =
= 2 * S (ABCD)4 = S (ABCD)2 = 382 = 19

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