Question

Найти предел
lim (n к бесконечности) ((3n^2-2n)/(3n^2-2n+5))^(n+2)

Answer 1

$( frac{ frac{3 n^{2} }{n^{2}}- frac{2n}{n^{2}} }{ frac{3n^{2}}{n^{2}}- frac{2n}{n^{2}}+ frac{5}{n^{2}} } )^{n+2}= ( frac{3- frac{2}{n} }{3- frac{2}{n}+ frac{5}{n^{2}} } )^{n+2}= ( frac{3}{3} )^{n+2} = 1^{n+2}=1$