Предмет: Алгебра, автор: KejVan

молю, решите пожалуйста

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Автор ответа: sedinalana

0

-sin(3x/2+π/4)+cos(3x/2+π/4)=0 разделим на cos(3x/2+π/4)
-tg(3x/2+π/4)+1=0
tg(3x/2+π/4)=1
3x/2+π/4=π/4+πk
3x/2=πk
x=2πk/3,k∈z

Автор ответа: KejVan

0

у тебя там ошибка, там 5п4

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