Question

Решите уравнение: 2x^3-7x^2+9=0

Answer 1

$2x^3-7x^2+9=0 \ (x-3)(x+1)(2x-3)=0 \ x-3=0= textgreater x=3 \ x+1=0= textgreater x=-1 \ 2x-3=0= textgreater x=1,5$