Предмет: Информатика, автор: 666778

Помогите решить пожалуйста(На 4 и 5 только)

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Автор ответа: smnoregrets
0
Логическая схема в приложении, однако функция не имеет смысла т.к.
F = (!A&BvC) v !C ВСЕГДА равно 1.
F = (!A&BvC) v !C = !A&B v C  v !C = !A&B v 1 = 1

Задание два:
F = !A & !(B v C)




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