Question

Вычислите предел
3 номер

Answer 1

$lim_{x to 2} frac{3x^2-5x-2}{2x^2-x-6}= lim_{x to 2} frac{(3x+1)(x-2)}{(2x+3)(x-2)}= lim_{x to 2} frac{3x+1}{2x+3}= frac{7}{7} =1$