Question

sin2xcos2x= -1/4 pomogite

Answer 1

sin2xcos2x=-1/4
2•sin2xcos2x=-1/4*2
sin4x=-1/2
4x=(-1)^narcsin(-1/2)+πn
4x=(-1)^(n+1)arcsin1/2+πn
4x=(-1)^(n+1)•π/6+πn
x=(-1)^(n+1)π/24+πn/4;n€Z