Question

Как найти производную функции y=tg2x-ctg2x

Answer 1

tg2x'=(2x)'·1/(cos2x)^2=2/(cos2x)^2.
Ctg2x'=-2/(sin2x)^2.
Y'=2/(cos2x)^2-(-2/(sin2x)^2)=2/(sin2xcos2x)^2=2/(0,5sin4x)^2.=4/(sin4x)^2