Question

решите тригонометрические неравенства

Answer 1

tgx≥√3
x∈[π/3+πk;π/2+πk,k∈z)

sinx≥1/2
x∈[π/6+2πk;5π/6+2πk,k∈z]

cosx≤√3/2
x∈[π/6+2πk;11π/6+2πk,k∈z]

ctgx≥√3
x∈(πk;π/6+πk,k∈z]