Question

(х-3)в квадрате=10х в квадрате-(3х-4)в квадрате

Answer 1

Решение:
$(x - 3)^{2} = 10 {x}^{2} - 3x + 4 \ {x}^{2} - 6x + 9 = 10 {x}^{2} - 3x + 4 \ - 9 {x}^{2} - 3x + 5 = 0 \ 9 {x}^{2} + 3x - 5 = 0 \ d = 9 - 4 times 9 times ( - 5) = 189 \ x1 = frac{ - 3 + sqrt{189} }{18} = frac{ - 1 + sqrt{21} }{6} \ x2 = frac{ - 3 - sqrt{189} }{18} = frac{ - 1 - sqrt{21} }{6}$