Question

Решите уравнение: (9-b)(b+9)+(4-b)^2=0

Answer 1

$(9-b)(b+9)+(4-b)^2=0 \ 9b+81-b^2-9b+16-8b+b^2=0 \ 97-8b=0 \ -8b=-97 \ b= frac{97}{8} =12 frac{1}{8}=12,125$