Предмет: Алгебра, автор: demyankovaalina

Найдите sin x, если sin x/2 =1/2 и 90°＜х/2＜180°

Ответы

Автор ответа: Аноним

0

x/2=180°-30°=150°
x=300°=270°+30°
sin300°<0
sin(270°+30°)=-cos30°=-√3/2

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