Question

cosx=8/17,0 больше х больше n/2 ctgx-?;sinx-? tgxvds -?

Answer 1

$cosx=frac{8}{17} \ sinx-? \ ctgx-? \ sin^{2}x=1-cos^{2}x \ sinx=sqrt{1-frac{64}{289}} \ sinx=frac{5}{17} \ ctgx=frac{cosx}{sinx}=frac{frac{8}{17}}{frac{5}{17}}=frac{8}{5}$

$tgx=frac{sinx}{cosx}=frac{frac{5}{17}}{frac{8}{17}}=frac{5}{8}$