Question

Решите уравнение f'(x) = 0:
f (x) = 3x^3 - 2x^2 - 1

Answer 1

f ' (x) = 3*3x^2 - 2*2x = 9x^2 - 4x

9x^2 - 4x = 0 
x (9x - 4) = 0 

x = 0 ;
x = 4/9