Предмет: Алгебра, автор: sofyamorozova14

найдите множество корней уравнения x^2-(p+2)x+2p=0

Ответы

Автор ответа: MizoriesKun

0

х²-(р+2)*х+2р=0

D=(p+2)²-4*2p=p²+2p+4-8p =p²-4p+4 =(p-2)² √D=p-2

x₁ = (p+2)+(p-2)=p+2+p-2=2p
x₂ = (p+2)-(p-2)=p+2-p+2 =4

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