Question

найдите множество корней уравнения x^2-(p+2)x+2p=0

Answer 1

х²-(р+2)*х+2р=0

D=(p+2)²-4*2p=p²+2p+4-8p =p²-4p+4 =(p-2)²    √D=p-2

x₁ = (p+2)+(p-2)=p+2+p-2=2p
x₂ = (p+2)-(p-2)=p+2-p+2 =4