Question

$frac{6}{x} + frac{6}{x + 1} = 5$
помогите плиз

Answer 1

$frac{6}{x} + frac{6}{x+1}-5=0 \ frac{6(x+1)+6x-5x(x+1)}{x(x+1)} =0 \ frac{6x+6+6x-5x^2-5x}{x(x+1)} =0 \ frac{-5x^2+7x+6}{x(x+1)} =0 \ left { {{5x^2-7x-6=0} atop {x neq 0; -1}} right. \ D=b^2-4ac=49+120=169=13^2 \ x_{1,2}= frac{-bpmsqrt{D}}{2a} \ x_{1}= frac{7+13}{10}=2 \ x_{2}= frac{7-13}{10} =-0.6 \ left { {{x=-0.6;2} atop {x neq -1;0}} right. \ x=-0.6;2$

Ответ: $x=-0.6; 2$

Answer 2

$frac{6(x+1)+6x}{x(x+1)} =5$
$frac{6x+6+6x}{ x^{2} +x} =5$
$12x+6=5 x^{2} +5x$
$5 x^{2} -7x-6=0$
$D= 7^{2} -4*5*(-6)=49+120=169$
$x_{1} = frac{7-13}{10}=- frac{6}{10}=-0.6$
$x_{2} = frac{7+13}{10} =2$