Question

(2х-5)²-(2х-3)(2х+3)=15 ;

(9х+2)(1-4х)+(5-6х)²=-32

решите уравнения :

Answer 1

1) $( 2x-5)^{2} - (2x - 3)(2x + 3) = 15$
$4 x^{2} - 20x + 25 - (4 x^{2} - 9) = 15$
$4 x^{2} - 20x + 25 - 4 x^{2} + 9 = 15$
$-20x + 34 = 15$
$-20x = 15 - 34$
$-20x = -19$
$x = frac{19}{20}$

2) $(9x + 2)(1 - 4x)+(5-6x)^{2} = -32$
$9x - 36 x^{2} + 2 - 8x + 25 - 60x + 36 x^{2} = -32$
$-59x + 27 = -32$
$-59x = -32 -27$
$-59x = -59$
$x = 1$