Question

(6c-2) в квадрате - (6c-3) в квадрате = 0

Answer 1

$(6c-2)^2 - (6c-3)^2 = 0$
$36c^2-24c+4-36c^2+36c-9=0$
$12c-5=0$
$c = frac{5}{12}$