Question

Помогите,пожалуйста.

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

$left { {{x^2-y=0} atop {y=(x+4)^2}} right. \\ x^2-(x+4)^2=0\\ x^2-x^2-8x-16=0\\ -8x-16=0\\ x=-2\\\ (-2)^2-y=0\\ y=4\\ Answer: (-2;4)$