Question

найдите x из пропорции 1)-62/58=x-500/522;
2)250+4x/333=59/67.

Answer 1

1)
-62/58 = (x-500)/522
(x-500)/522 = -62/58
(x-500)/522 = -31/29
x-500 = -31/29*522
x-500 = -31*18
x-500 = -558
x = -558-500
x = -1058

2)
(250+4x)/333 = 59/67
250+4x = 59/67*333
250+4x = 19 314/67
4x = 19314/67-250
4x = 19314/67-16750/67
4x = 2564/67
x = 2564/67*1/4
x = 2564/268 = 641/67 = 9 целых 38/67