Question

Решите уравнение $||x^2-x|-x^2|=4$

Answer 1

$||x^2-x|-x^2|=4 \ \ \ 1)|x^2-x|-x^2=4 \ 2)|x^2-x|-x^2=-4 \ \1)x^2-x-x^2=4,x^2-x geq 0 \ -(x^2-x)-x^2=4,x^2-x textless 0 \ x=-4 \\2)x^2-x-x^2=-4,x^2-x geq 0 \ -(x^2-x)-x^2=-4,x^2-x textless 0 \ x=4$

Ответ: x=-4,x=4