Question

Решите пж это уравнение

Answer 1

ОДЗ:
$3x^2-5x+2 geq 0 \ D=25-24=1 \ x_1=(5-1)/6= frac{2}{3} \ x_2=(5+1)/6=1 \ xin (-infty; frac{2}{3}] cup [1;+infty)$

$left { {{5-3x=3x^2-5x+2} atop {5-3x=-3x^2+5x-2}} right. = textgreater left { {{3x^2-2x-3=0} atop {3x^2-8x+7=0}} right. \ \ 3x^2-2x-3=0 \ D=4+36=40=(2 sqrt{10})^2 \ x_1= frac{2+2 sqrt{10} }{6}(:2)= frac{1+ sqrt{10} }{3} \ x_2= frac{1- sqrt{10} }{3} \ \ 3x^2-8x+7=0 \ D=64-84=-20 \ xin emptyset \ \ x_1=frac{1+ sqrt{10} }{3} \ x_2=frac{1- sqrt{10} }{3}$