Question

1) найдите g'(p/36) если g(x)=sin24x/cos12x
2) Найдите y'(5p/4), если y(x)=9√2 sinx- 7 tgx

Answer 1

1
g(x)=sin24x/cos12x
g(x)=2sin12x*cos12x/cos12x
g(x)=2sin12x
g`(x)=2*12*cos12x=24cos12x
g`(π/36)=24cosπ/3=24*1/2=12
2
y(x)=9√2sinx-7tgx
y`(x)=9√2cosx-7/cos²x
y`(5π/4)=9√2cos(5π/4)-1/cos²(5π/4)=9√2*(-√2/2)-7:1/2=-9-14=-23