Question

Найдите корни уравнений:
Номер 5.20.

Answer 1

$16x(2 - x) + (4x - 5)^{2} = 0 \ 32x - 16 {x}^{2} + 16 {x}^{2} - 40x + 25 = 0 \ 32x - 40x = - 25 \ - 8x = - 25 \ x = frac{25}{8} \ x = 3 frac{1}{8}$
$9y(y + 6) - (3y + 1)^{2} = 1 \ 9 {y}^{2} + 54y - (9 {y}^{2} + 6y + 1) = 1 \ 9 {y}^{2} + 54y - 9 {y}^{2} - 6y - 1 = 1 \ 54y - 6y = 2 \ 48y = 2 \ y = frac{2}{48} \ y = frac{1}{24}$

Answer 2

Спасибо