Предмет: Алгебра, автор: smirnovar2016

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Автор ответа: Аноним

1)сos191=cos(101+90)=-sin101
34/(cos^2101+sin^2101)=34/1=34
2)cos122=cos(180-58)= -cos58
2cos58/(-cos58)=-2
3) cos207=cos(180+27)= -cos27
6(-cos27)/cos27=-6

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