Question

(корень 3 + i ) : (корень 2 - i * корень 3)

Answer 1

(√3+i)/(√2-i√3)=(√3+i)*(√2+i√3)/(√2-i√3)(√2+i√3)=
=[√6+i√2+3i-√3]/(4+3)=(√6-√3)/7+(3+√2)i/7