Question

Решите пожалуйста!!!!
${x}^{6} - {x}^{4} - {x}^{2} + 1$
$8 {x}^{3} - frac{1}{27}$

Answer 1

x⁶-x⁴-x²+1=x⁴*(x²-1)-(x²-1)=(x²-1)*(x⁴-1)=(x-1)*(x+1)*(x²-1)*(x²+1)=
=(x-1)*(x+1)*(x-1)*(x+1)*(x²+1)=(x-1)²*(x+1)²*(x²+1).
8x³-1/27=(2x)³-(1/3)³=(2x-1/3)*(4x²+(2/3)*x+1/9).