Предмет: Физика, автор: катя20011122

кондинсатор был заряжен до 20В.При разрядке конденсатора в электрической цепи выделилась энергия 0,1 Дж. Какой заряд был на обкладке конденсатора?

Ответы

Автор ответа: fatt52

U=20 B W=0.1 Дж q=?
===
W=q*U/2
q=2*W/U=2*0.1/20=0.01 Кл
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