Question

Решите систему уравнений:
Log9 x-log9 y=1
Log4 (x+7y)=3

Answer 1

$log_{9}(x) - log_{9}(y) = 1 \ log_{4}(x + 7y) = 3 \ \ log_{9}( frac{x}{y} ) = 1 \ log_{4}(x +7y) = 3 \ \ frac{x}{y} = 9 \ x + 7y = 12 \ \ x = 9y \ x + 7y = 12 \ \ 9y + 7y = 12 \ 16y = 12 \ y = frac{12}{16} = frac{3}{4} \ \ x = 9 times frac{3}{4} = frac{27}{4}$

Answer 2

Спасибо огромное !