Question

Решите уравнение:
$0,3x ^{9} -2,4=0$
$frac{1}{8} x ^{4} -2=0$
$sqrt[5]{2x+8} =-1$
$sqrt[3]{7-4x} =4$

Answer 1

$0,3x ^{9} -2,4=0 \ 0.3x^9=2.4 \ x^9=8 \ x= sqrt[9]{8}$

$frac{1}{8} x ^{4} -2=0 \ frac{1}{8} x ^{4}=2 \ x^4=16 \ x=pm 2$

$sqrt[5]{2x+8} =-1 \ 2x+8=-1 \ 2x=-9 \ x=-4.5$

$sqrt[3]{7-4x} =4 \ 7-4x=64 \ -4x=57 \ x=-14.25$