Question

Потогите пожлауйста строчно с 317!

Answer 1

sinx ~ x, x ->0
tgx ~ x, x -> 0

$lim_{x to 0} frac{tg2x}{sin5x} = lim_{x to 0} frac{2x}{5x}= lim_{x to 0} frac{2}{5}= frac{2}{5}$