Question

Anonim the god
3-4 sin^2 t=0
sin^2-sin t=0
4sin^2 t-1=0
2sin^2 t+sin t=0

Answer 1

$1)3-4 sin^2 t=0 \4sin^2t=3 \sin^2t= frac{3}{4} \sint=sqrt{frac{3}{4} }= frac{sqrt{3}}{2} \t_1= frac{pi}{3} +2pi n, n in Z \t_2= frac{2pi}{3} +2pi n, n in Z \sint=-sqrt{frac{3}{4} }=- frac{sqrt{3}}{2} \t_3= -frac{pi}{3} +2pi n, n in Z \t_4= -frac{2pi}{3} +2pi n, n in Z \2)sin^2t-sin t=0 \sint(sint-1)=0 \sint=0 \t_1=pi n, n in Z \sint=1 \t_2= frac{pi}{2} +2pi n, n in Z$
$3)4sin^2 t-1=0 \4sin^2t=1 \sin^2t= frac{1}{4} \sint=sqrt{ frac{1}{4} }= frac{1}{2} \t_1= frac{pi}{6} +2pi n, n in Z \t_2= frac{5pi}{6} +2pi n, n in Z \sint=-sqrt{ frac{1}{4} }= -frac{1}{2} \t_3= -frac{pi}{6} +2pi n, n in Z \t_4= -frac{5pi}{6} +2pi n, n in Z \4)2sin^2 t+sin t=0 \sint(2sint+1)=0 \sint=0 \t_1=pi n, n in Z \sint= -frac{1}{2} \t_2= -frac{pi}{6} +2pi n, n in Z \t_3= -frac{5pi}{6} +2pi n, n in Z$